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In a group of persons, 70% of the persons are male and 30% of the persons are married. If two-sevenths of the males are married, what fraction of the females is single?

  1. A.2/7
  2. B.1/3
  3. C.3/7
  4. D.2/3
▶ Answer & Explanation

Correct answer: C. 3/7

Let the total number of persons be 100. Then, males are 70 and females are 30. The number of married males is (2/7) * 70 = 20. If 30% of the total persons are married, then 30 persons are married. Since 20 married persons are male, the remaining 10 married persons must be female. Thus, out of 30 females, 10 are married, which means 20 females are single. Therefore, the fraction of single females is 20/30, which simplifies to 2/3. This calculation seems to contradict the known answer. Re-evaluating: If 70% are male, 30% are female. If 30% of the total are married, 70% are single. Married males = (2/7) * 70 = 20. Total married = 30. Married females = 30 - 20 = 10. Total females = 30. Single females = 30 - 10 = 20. Fraction of single females = 20/30 = 2/3. There must be a mistake in my derivation or understanding of the question's intent based on the provided correct answer. Let's assume the correct answer C (3/7) is correct and work backward or re-examine. If 3/7 of females are single, and there are 30 females, then (3/7)*30 = 90/7 females are single, which is not a whole number, indicating an issue. Let's re-read. 70% male, 30% female. 30% married, 70% single. Married males = (2/7) * 70 = 20. Total married = 30. Married females = 30 - 20 = 10. Total females = 30. Single females = 30 - 10 = 20. Fraction single females = 20/30 = 2/3. It seems the provided correct answer might be incorrect given standard percentage calculations, or the question implies a specific setup not immediately obvious. However, if we are to justify C (3/7), let's check if any other interpretation fits. If total is 100, M=70, F=30. Married M = 20. Total Married = 30. Married F = 10. Single F = 20. Fraction single F = 20/30 = 2/3. Let's assume the question meant something else. The question is a standard percentage and fraction problem. Let's trust the math. The math consistently points to 2/3. Given the constraint that the provided answer 'C' (3/7) is correct, it suggests an error in either the question statement, the provided options, or the known correct answer. However, if we MUST justify 3/7, let's consider alternative frameworks. Suppose the total group is a multiple of 7 and 10, say 70. Males = 49, Females = 21. Married Males = (2/7)*49 = 14. Total Married = 30% of 70 = 21. Married Females = 21 - 14 = 7. Total Females = 21. Single Females = 21 - 7 = 14. Fraction Single Females = 14/21 = 2/3. The result remains 2/3. It is highly probable that the provided correct answer is erroneous for this question. However, if we assume there's a typo in the question and the fraction of married males was, for example, 3/7 of males: Married males = (3/7)*70 = 30. Total married = 30. Married females = 0. Single females = 30. Fraction single females = 30/30 = 1. This is not 3/7. Let's try another interpretation for 3/7 to be the answer. If 3/7 of females are single, and females are 30% of total. Let total be T. Females = 0.3T. Single Females = (3/7) * 0.3T = 0.9T/7. Married Males = (2/7) * 0.7T = 0.2T. Total Married = 0.3T. Married Females = 0.3T - 0.2T = 0.1T. So, Single Females = Total Females - Married Females = 0.3T - 0.1T = 0.2T. Fraction of Single Females = Single Females / Total Females = 0.2T / 0.3T = 2/3. There seems to be a consistent result of 2/3. I cannot derive 3/7 based on the problem statement and standard logic. The explanation will follow the logic that leads to 2/3, as it is the mathematically derived answer, acknowledging the discrepancy with the known answer C.

Source: UPSC csat 2011

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