csatmedium

30 g of sugar was mixed in 180 ml water in a vessel A, 40 g of sugar was mixed in 280 ml of water in vessel B and 20 g of sugar was mixed in 100 ml of water in vessel C. The solution in vessel B is

  1. A.sweeter than that in C.
  2. B.sweeter than that in A.
  3. C.as sweet as that in C.
  4. D.less sweet than that in C.
▶ Answer & Explanation

Correct answer: A. sweeter than that in C.

Sweetness is determined by the concentration of sugar in water. Vessel A has a concentration of 30g/180ml = 1/6 g/ml. Vessel B has a concentration of 40g/280ml = 1/7 g/ml. Vessel C has a concentration of 20g/100ml = 1/5 g/ml. Comparing these concentrations, 1/5 is the highest, followed by 1/6, and then 1/7. Therefore, vessel C is the sweetest, followed by vessel A, and then vessel B is the least sweet.

Source: UPSC csat 2016

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