A person walks 12 km due north, then 15 km due east, after that 19 km due west and then 15 km due south. How far is the from the starting point?
- A.5 km
- B.9 km
- C.37 km
- D.61 km
▶ Answer & Explanation
Correct answer: B. 9 km
The person moves 12 km North and then 15 km South, resulting in a net displacement of 3 km South (15 km South - 12 km North). Simultaneously, the person moves 15 km East and then 19 km West, resulting in a net displacement of 4 km West (19 km West - 15 km East). The final position is 3 km South and 4 km West of the starting point. Using the Pythagorean theorem, the distance from the starting point is the square root of (3^2 + 4^2), which equals the square root of (9 + 16) or the square root of 25, resulting in 5 km.
Source: UPSC csat 2016